K4 Plaintext and K5 Ciphertext - Proposed
- Zackery Belanger
05 January 2026
Another crack at K4:
TYNE
SDUALFORMTRUESIGNEASTNORTHEASTD
ISCPLAYAVOIDTWINPARTICLESFATBER
LINCLOCKWOMANSWINGSBUTMAGICATOM
TYNES DUAL FORM
TRUES IGN EAST NORTHEAST
DISC PLAYA VOID
TWIN PARTICLES
FAT-
BERLIN CLOCK WO
-MAN SWINGS BUT MAGIC ATOM
Proposed K5 ciphertext (03 Nov 2024):
UEOSFOMJDDEYUMIOISIRYHDRGEBHHKEQ
HXУOЫЙAOЦЧMXЧЙЧДПУCФЮЗ
XHЖPБЫЖЦФЪБCЧPПMЦЧШTXККЖПЩЗПЙXГO
Kryptos Resources
To start I’m sharing a PDF that has the Kryptos ciphertext and table with a font and kerning that closely matches the sculpture.
- Zackery Belanger
17 December 2025
Updated Work In Progress
- Zackery Belanger
25 November 2025
The most recent release of my Kryptos work can be found here. Previous releases remain available below.
Proposed K4 plaintext (18 Nov 2025, corrected 10 Dec 2025):
TYNED DUAL FUME VENT SITS EAST NORTHEAST
FUME DUCTS WELD BY FOOT
FAITH TEARS BERLIN
CLOCK WOMAN ENCRYPTS
MAGIC JOLTS
Proposed K5 ciphertext (03 Nov 2024):
UEOSFOMJDDEYUMIOISIRYHDRGEBHHKEQ
HXУOЫЙAOЦЧMXЧЙЧДПУCФЮЗ
XHЖPБЫЖЦФЪБCЧPПMЦЧШTXККЖПЩЗПЙXГO
Kryptos Last Shot
- Zackery Belanger
(updated 19 November 2025)
New document describing last-minute solution attempt.
TYNE
DDUALFUMEVENTSITSEASTNORTHEASTF
UMEDUCTSWELDBYFOOTFAITHTEARSBER
LINCLOCKWOMANDECRYPTSMAGICJOLTS
TYNED DUAL FUME VENT SITS EAST NORTHEAST
FUME DUCTS WELD BY FOOT
FAITH TEARS BERLIN CLOCK
WOMAN DECRYPTS MAGIC JOLTS
On November 20 2025 the secrets of Jim Sanborn’s Kryptos will be auctioned off to the highest bidder. This impending event drove the difficult decision to release my incomplete work on Kryptos in mid October, including proposed K3 WONDERFUL and a new ciphertext that I thought was K5, though this conflicts with information recently released. In early November I also found a potential solution to K4 (or maybe it’s K5). On November 18 I refined that potential solution.
Kryptos New Ciphertext (03 Nov 2024):
UEOSFOMJDDEYUMIOISIRYHDRGEBHHKEQ
HXУOЫЙAOЦЧMXЧЙЧДПУCФЮЗ
XHЖPБЫЖЦФЪБCЧPПMЦЧШTXККЖПЩЗПЙXГO
Kryptos K3 WONDERFUL Alphabet (July 2024):
AGOLJFYXQHWZSMTNCVKRPUIB?DE
The first 32 characters of the new ciphertext are from the Latin alphabet, and the final 54 characters are from the Cyrillic alphabet.
The derivations of the new ciphertext, K3 WONDERFUL, the first 100 steps of the last solution attempt, and a mess of other layers and notes, can be found in the document linked above.
Three books are required in the most recent K4 solution attempt, in this order:
Beckett, Samuel. “Rockaby And Other Short Pieces”. Grove Press, Inc. New York. 1981.
Davis, Robin J. and Butler, Lance St. J. “Make Sense Who May: Essays on Samuel Beckett’s Later Works”. Barnes & Noble Books. Totowa, New Jersey. 1988.
Wordsworth, William. “The Poetical Works of William Wordsworth”. Volume II. Little, Brown and Company. Boston. 1859
Wordsworth was so widely published that this particular edition may not be necessary, and/or another edition could be more useful.
The K4 method is many-layer and relies on clues expressed in the ciphertext at each layer. A more careful explanation of these layers and a writeup of the rest of it is underway, but will take time. Here’s an outline of the basic structure:
Pull a custom alphabet from the K4 ciphertext itself by eliminating duplicate characters. Include the ?.
Apply a “CORYMB” transposition, which mimics the inflorescence structure (take off the first character, then the last, then the second, then second-to-last, etc.).
Use the final 98 characters of the six endings in “Rockaby” as running keys over and over, choosing each depending on the previous clue. There are some transpositions in there as well, indicated by the clues.
Shift every character in the entire ciphertext by values 1 - 6, alternating positive and negative, based on the sequence of six endings used. (pages 147 - 148)
Apply a running key from one of the previous Kryptos solutions.
Assemble a new ciphertext by sequentially assembling a character from the previous 97 layers.
Apply running keys from “Make Sense Who May” based on the clues.
Apply 27 running key simultaneously from Wordsworth’s “The Wishing Gate” and “The Wishing Gate - Destroyed”. Keys are chosen based on the presence of the terms VOW, TEAR, and LOVE.
The previous 17 layers produce a grid, from which the K4 plaintext can be painstakingly extracted. Use a sequence from the custom alphabet as markers, and use the content of the running keys from “Make Sense Who May” and Wordsworth to guide selection.
-Zackery Belanger
05 November 2025 (updated 19 November 2025)
Kryptos K3 Gimlet Trick
I call this the K3 Gimlet Trick, and I believe this is the method Ed Scheidt intended.
Qs are wild and the italicized definitions are paraphrased from Merriam Webster.
Put K3 in monospace with row lengths as they are in the sculpture, and no ?. Identify GIMLET - to pierce - at the top of column 24.
ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIA
CHTNREYULDSLLSLLNOHSNOSMRWXMNE
TPRNGATIHNRARPESLNNELEBLPIIACAE
WMTWNDITEENRAHCTENEUDRETNHAEOE
TFOLSEDTIWENHAEIOYTEYQHEENCTAYCR
EIFTBRSPAMHHEWENATAMATEGYEERLB
TEEFOASFIOTUETUAEOTOARMAEERTNRTI
BSEDDNIAAHTTMSTEWPIEROAGRIEWFEB
AECTDDHILCEIHSITEGOEAOSDDRYDLORIT
RKLMLEHAGTDHARDPNEOHMGFMFEUHE
ECDMRIPFEIMEHNLSSTTRTVDOHW
Reduce the column width to 24. Identify LITANY EAST - a sizable set... to the right - at the top of the last column.
ENDYAHROHNLSRHEOCPTEOIBI
DYSHNAIACHTNREYULDSLLSLL
NOHSNOSMRWXMNETPRNGATIHN
RARPESLNNELEBLPIIACAEWMT
WNDITEENRAHCTENEUDRETNHA
EOETFOLSEDTIWENHAEIOYTEY
QHEENCTAYCREIFTBRSPAMHHE
WENATAMATEGYEERLBTEEFOAS
FIOTUETUAEOTOARMAEERTNRT
IBSEDDNIAAHTTMSTEWPIEROA
GRIEWFEBAECTDDHILCEIHSIT
EGOEAOSDDRYDLORITRKLMLEH
AGTDHARDPNEOHMGFMFEUHEEC
DMRIPFEIMEHNLSSTTRTVDOHW
Rotate 90 degrees to the right. Identify WHENCE - out of which place - at the top of column 8.
DAEGIFWQEWRNDE
MGGRBIEHONAOYN
RTOISONEEDRHSD
IDEEETAETIPSHY
PHAWDUTNFTENNA
FAOFDEACOESOAH
ERSENTMTLELSIR
IDDBIUAASNNMAO
MPDAAATYERNRCH
ENREAEECDAEWHN
HEYCHOGRTHLXTL
NODTTTYEICEMNS
LHLDTOEIWTBNRR
SMODMAEFEELEEH
SGRHSRRTNNPTYE
TFIITMLBHEIPUO
TMTLEABRAUIRLC
RFRCWETSEDANDP
TEKEPEEPIRCGST
VULIIREAOEAALE
DHMHETFMYTETLO
OELSRNOHTNWISI
HEEIORAHEHMHLB
WCHTATSEYATNLI
Reduce column width to 8. Identify HINGE - to swing - at the top of the last column.
DAEGIFWQ
EWRNDEMG
GRBIEHON
AOYNRTOI
SONEEDRH
SDIDEEET
AETIPSHY
PHAWDUTN
FTENNAFA
OFDEACOE
SOAHERSE
NTMTLELS
IRIDDBIU
AASNNMAO
MPDAAATY
ERNRCHEN
REAEECDA
EWHNHEYC
HOGRTHLX
TLNODTTT
YEICEMNS
LHLDTOEI
WTBNRRSM
ODMAEFEE
LEEHSGRH
SRRTNNPT
YETFIITM
LBHEIPUO
TMTLEABR
AUIRLCRF
RCWETSED
ANDPTEKE
PEEPIRCG
STVULIIR
EAOEAALE
DHMHETFM
YTETLOOE
LSRNOHTN
WISIHEEI
ORAHEHMH
LBWCHTAT
SEYATNLI
Rotate 90 degrees to the right.
SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGED
EBRISTHATENCUMBEREDTHELOWERPARTOFTHEDOORWA
TWASREMOVEDWITHTREMBLINGHANDSIMADEATINYBRE
ACHINTHEUPPERLEFTHANDCORNERANDTHENWIDENING
THEHOLEALITTLEIINSERTEDTHECANDLEANDPEEREDI
NTHEHOTAIRESCAPINGFROMTHECHAMBERCAUSEDTHEF
LAMETOFLICKERBUTPRESENTLYDETAILSOFTHEROOMW
ITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ
I call this solution K3 THINGS, and another solution - K3 WONDERFUL - also exists.
K3 THINGS was first solved using different methods in the 1990s by Denny McDaniels at the NSA; David Stein at the CIA; and civilian Jim Gillogly, all independent of each other.
-Zackery Belanger
Released 30 January 2025
-Zackery Belanger
Released 21 September 2024
Kryptos Structure: The Tomb of Tutankhamun
A PDF of this image is available here.